
Kelsie C. answered 03/02/16
Tutor
4
(1)
Math, English, Memorization Techniques, Proofreading
This is a system of equations.
The first one states that one number is 2 more than 2 times the second number. Let's assign a as the first number, and b as the second:
a = 2b + 2
The second equation states that the product of these two number is 40:
a x b = 40
Now, in the first equation, a is defined using b. This means that we can substitute the right side of the first equation for a in the second equation:
(2b + 2) x b = 40
Now we have one variable to solve for (right now anyway).
2b2 + 2b = 40 Divide by 2 on both sides
b2 + b = 20 Subtract 20 from both sides
b2 + b - 20 = 0 Use the quadratic equation or completing the square to simplify
(b + 5)(b - 4) = 0 Set both sets of parentheses equal to 0
b + 5 = 0, b = -5
b - 4 = 0, b = 4
Notice that we have 2 answers for b. We can take these answers and plug them back in to the first equation to solve for a:
a = 2b + 2
a = 2(-5) + 2
a = -10 + 2
a = -8
a = 2b + 2
a = 2(4) + 2
a = 8 + 2
a = 10
So our 2 answers are -5 and -8, or 4 and 10. We should check to make sure that they work, however, by plugging them into the second equation:
a x b = 40
-5 x -8 = 40 This is correct, so -5 and -8 is an answer
a x b = 40
4 x 10 = 40 This is also correct, so 4 and 10 is also an answer.