could someone help me do this?

Question

Solve the following equation.

x(4x-19)=5

 

x = ______ , ______

Answer 1

First, we distribute the x:

 

x(4x - 19) = 5

4x² - 19x = 5

 

Now, we subtract 5 from both sides to set the equation equal to zero:

 

4x² - 19x - 5 = 0

 

Then, we factor the trinomial:

 

(4x + 1)(x - 5) = 0

 

To find our zeroes, we set each factor equal to zero and solve:

 

4x + 1 = 0

4x = -1

x = -1/4

 

x - 5 = 0

x = 5

 

Our zeroes are x = -1/4 and x = 5