how to solve this equation? my teacher didnt teach me how to do this?

Question

Solve the following equation.

 

3a²-5a+2=0

Answer 1

We can factor the equation:

 

3a² - 5a + 2 = 0

(3a - 2)(a - 1) = 0

 

Next, we set each factor equal to zero and solve to get our zeroes:

 

3a - 2 = 0

3a = 2

a = 2/3

 

a - 1 = 0

a = 1

 

Our zeroes are a = 2/3 and a = 1.