could someone help me with this math problem?

Question

Factor completely 
a⁴ 4-a²-6

Answer 1

4a^4 -a^2 -6

a^2= 1/8 +/- (1/8)sqr(1 +96)

a^2 = 1/8+/- sqr(97)/8

a^2 = (1+/-sqr97)/8

a^2 = 1+sqr97/8, 1 -sqr97/8

a = +/-sqr(1+sqr97/8), +/- sqr(1-sqr97/8)

4 factors are

(a-sqr(1+sqr97/8)(a+sqr(1+sqr97/8)(a+sqr(1-sqr97/8)(a-sqr(1-sqr97)

there are no integer factors, just irrational factors

unless you meant something different by a^4 4 -a^2 -6

maybe you accidentally hit "4" twice so you really meant

a^4 -a^2 -6

then

let x = a^2

x^2 -x -6

=(x-3)(x+2)

=(a^2-3)(a^2+2)

that's as far as most people would go, for integer factors