could someone help me with this math problem?

Question

Factor the following trinomial.

6r² +r-2

 

i'm so confused what they want me to do 

Answer 1

6r² + r -2

 

We can factor by grouping:

Multiply the coefficient of the square term, 6, by

the constant, -2 ...  6(-2) = -12

Look for factors of -12 that add to 1 since that is

the coefficient of the r term...

-12 = 4(-3) and 4-3 = 1

Replace the r with -3r + 4r

 

6r² - 3r + 4r -2     Note this actually the same as the original equation

                           since -3r+4r = r

 

Now factor the first 2 terms and the 2nd two terms

 

3r(2r-1) + 2(2r-1)

 

= (3r+2)(2r-1)