
Michael W.
asked 02/24/16I need help with this math problem?
Factor the following by taking out the greatest common factor.
8x3 +3x2
but neither have a factor. please help me
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2 Answers By Expert Tutors

David W. answered 02/24/16
Tutor
4.7
(90)
retired
Michael, get a grip!!
See -- https://www.wyzant.com/resources/answers/190191/could_someone_help_me_find_the_gcf
You are wrong to say that neither 8x3 nor 3x2 have factors.
The factors of 8x3 are: 1, 2, 4, 8, x, x2, x3 [they all divide into 8x3 evenly]
The factors of 3x2 are: 1, 3, x x2 [they all divide into 3x2 evenly]
Now, which factor is the largest (greatest) one that they share (common)?
[note: given that x could represent any number, we leave it that way]
So, looks like there is no number, but there is an x2 that is the largest shared factor. Let's factor out the x2:
x2(8x+3)
Here, try this one:
What is the GCF of: 21x2 + 7x

Andrew M. answered 02/24/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
8x3 + 3x2
Both are divisible by x2
8x3+3x2 = 8(x2)(x)+3x2
factor x2 from both terms
x2(8x + 3) is the answer
********************
Think of this in the fact that x
represents a number. What if
x was 2? We would have
8(23) + 3(22)
= 8(8) + 3(4)
= 8(4)(2) + 3(4)
You can see that both are divisible by 4
= 4[8(2) + 3]
= 22[8(2) + 3]
Putting x back in place of 2 we have
x2(8x+3)
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David W.
02/24/16