Oscar A. answered 02/24/16
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Equation to solve is:
6x2+12x+14=0
The solutions are:
x1=−1+233√ix2=−1−233√i
Explanation
STEP1: Find coefficients a , b and c.
In this example a=6,b=12,c=14
STEP2: Plug in the values for a, b, and c into the quadratic formula
x1,2=−b±b2−4ac−−−−−−−√2a
x1,2=−12±122−4⋅6⋅14−−−−−−−−−−−√2⋅6
STEP3: Simplify expression under the square root.
x1,2=−12±−192−−−−√12
STEP4: Solve for x
x1=−12 + −192−−−−√12=−1+233√i
x2=−12 − −192−−−−√12=−1−233√i
6x2+12x+14=0
The solutions are:
x1=−1+233√ix2=−1−233√i
Explanation
STEP1: Find coefficients a , b and c.
In this example a=6,b=12,c=14
STEP2: Plug in the values for a, b, and c into the quadratic formula
x1,2=−b±b2−4ac−−−−−−−√2a
x1,2=−12±122−4⋅6⋅14−−−−−−−−−−−√2⋅6
STEP3: Simplify expression under the square root.
x1,2=−12±−192−−−−√12
STEP4: Solve for x
x1=−12 + −192−−−−√12=−1+233√i
x2=−12 − −192−−−−√12=−1−233√i