Question 1 is unclear. are you talking about rolling a four or lower as the sum of the two dice? In which case it is 1/6.
Six possibilities (1,1),(1,2),(1,3),(2,1),(2,2), and (3,1) out of 36.
Or of rolling a 4 or less on either die? Try:
1 - Probability (rolling only 5 or 6) = 1 - (1/3)(1/3) = 1 - 1/9 = 8/9
Question 2 is rapidly done using Pascal's Triangle, the coefficients of a fifth order equation are 1,5,10,10,5,1.
So the second term is 5a4b = 5(2)4(-1) = -5(16x4) = -80x4