Possibilities

Question

The length of a rectangle is 5 inches more than twice the width. If the area is to be at least 18 square inches, what are the possibilities for the width?

Answer 1

The area for a rectangle is

length(L)* width(W)= Area(A)

 

L*W=18in²

 

The problem tells us that the length is (=), 5 inches more (+5), than twice the width (2W)

L= 2W+5in

 

Use substitution to find the (W) that will get an area of at least 18.  This will get you the smallest value that (W) can be.  Any other sets of (L) and (W) that fit the L= 2W+5in equation and are larger than your first answer will satisfy the criteria.