Use the formula for either sum of cubes or difference of cubes. (Carefully choose the right formula from your book.) Factor 64x^3 + 27.

Question

A:(4x + 3)(16x^2 + 12x + 9)

B: (4x + 3)(4x^2 - 12x + 9)

C:(4x + 3)(64x^2 - 12x + 27)

D: (4x + 3)(16x^2 - 12x - 9)

E: (4x + 3)(16x^2 - 12x + 9)

Answer 1

Caleb

64x³ - 27
is equivalent to
(4x)³-3³

The basic formula to factor the difference of two cube is the following

a³+b³ = (a+b)(a^2-ab+b²)

So in our case
64x³+27 = (4x+3)(16x^2-12x+9)

E is the correct answer.