Shada S. answered 01/26/16
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Math, Physics, and Chemical Engineering Tutor
Let the length of the rectangular garden be L and the width of the garden be W.
The length of the garden is 5 less than twice the width
so L = 2 W - 5 , since it is 5 less than, so we have the -5, twice the width, so we have 2 W.
L = 2W - 5 let's call this equation 1
Also, we are given that the perimeter of the garden is 95 yards. For a rectangular shape, we know that the perimeter is the sum the lengths and widths of the rectangle so
Perimeter = 2 L + 2 W = 95 yards let's call this equation 2
Now we have 2 equations and 2 unknowns, so we can solve for the unknowns.
From equation 1 we have L in terms of W, if we substitute equation 1 in equation 2 we get:
2 ( 2W - 5) + 2 W = 95 yards, now solve for W
4 W - 10 + 2 W = 95
6 W - 10 = 95
6 W = 105
W = 105/6 = 17.5 yards
substitute W = 17.5 in equation 1 to find L
L = 2*(17.5) - 5 = 30 yards