Ben G. answered 01/22/16
Tutor
New to Wyzant
Veterinarian and Wildlife Disease Ecologist Tutoring Math and Science
For the quadratic formula, you take the equation 0=ax2+bx+c, where a, b, and c are the numbers associated with x2, x, and the last number, respectively. So here, a=3, b=5, and c=5. To solve for x, you plug those values into the quadratic formula, which is:
x= [-b + or - sqrt(b2-4ac)]/2a
Here, we are solving for x at y=0. So x= [-5 + or - sqrt(52 -4*3*5)]/(2*3), which simplifies:
x= [-5 + or - sqrt(25-60)]/6
x= [-5 + or - sqrt(-35)]/6
x= [-5 + or - i*sqrt(35)]/6, which is the third option down.
Recall that i is the square root of -1, so we start with sqrt(-35) = sqrt(-1*35) = sqrt(-1)*sqrt(35) = i*sqrt(35).
If you have any other math questions, I offer online tutoring and would be happy to help with your understanding of these concepts!