Edward C. answered • 01/19/16

Caltech Grad for math tutoring: Algebra through Calculus

If 3 numbers form an arithmetic sequence with a common difference of 11 then the 3 numbers are

X, X+11, X+22

If the first is decreased by 6, the second is decreased by 1 and the third is doubled then the 3 new numbers are

X-6, X+10, 2X+44

If these 3 new numbers form a geometric sequence then the successive terms have a common ratio, which means

(X+10)/(X-6) = (2X+44)/(X+10)

Solve for X