Inactive Tutor answered • 11/11/13
Tutor
New to Wyzant
Hi again M;
√(2x2-7)
As you already know, we cannot square root anything less than zero. We therefore must find the minimum value of 2x2-7
0≤2x2-7
7≤2x2
7/2≤x2
3.5≤x2
√3.5≤x
-√3.5≥x Note the fact that because I multiplied the figure by a negative sign, I had to reverse the less than to greater than signage.
domain is (-∞, -√3.5]U[√3.5, +∞)
Inactive Tutor
I just updated my )(, parentheses, to ][, brackets, because I realized the same thing.
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11/11/13
Inactive Tutor
We cannot render the equation less than zero. The values between these numbers are NOT included in the domain.
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11/11/13
M K.
Alright, thanks Ms. Vivian! You've been a great help!
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11/11/13
M K.
Oh yes, I just realized that. Even though it's negative and positive, there won't be anything in between because it won't fit the sign.
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11/11/13
M K.
11/11/13