Vivian L. answered • 11/11/13

Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH

^{2}-7)

^{2}-7

^{2}-7

^{2}

^{2}

^{2}

Vivian L.

11/11/13

Vivian L.

11/11/13

M K.

11/11/13

M K.

11/11/13

M K.

asked • 11/11/13How I find the domain of √(2x^{2}-7)? Please include all steps so I know what I'm doing, because I have no idea how to find the answer. Thanks!

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Vivian L. answered • 11/11/13

Tutor

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Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH

Hi again M;

√(2x^{2}-7)

As you already know, we cannot square root anything less than zero. We therefore must find the minimum value of 2x^{2}-7

0≤2x^{2}-7

7≤2x^{2}

7/2≤x^{2}

3.5≤x^{2}

√3.5≤x

-√3.5≥x Note the fact that because I multiplied the figure by a negative sign, I had to reverse the less than to greater than signage.

domain is (-∞, -√3.5]U[√3.5, +∞)

Vivian L.

I just updated my )(, parentheses, to ][, brackets, because I realized the same thing.

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11/11/13

Vivian L.

We cannot render the equation less than zero. The values between these numbers are NOT included in the domain.

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11/11/13

M K.

Alright, thanks Ms. Vivian! You've been a great help!

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11/11/13

M K.

Oh yes, I just realized that. Even though it's negative and positive, there won't be anything in between because it won't fit the sign.

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11/11/13

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M K.

11/11/13