How I find the domain of √(2x

^{2}-7)? Please include all steps so I know what I'm doing, because I have no idea how to find the answer. Thanks!-
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Middletown, CT

Hi again M;

√(2x^{2}-7)

As you already know, we cannot square root anything less than zero. We therefore must find the minimum value of 2x^{2}-7

0≤2x^{2}-7

7≤2x^{2}

7/2≤x^{2}

3.5≤x^{2}

√3.5≤x

-√3.5≥x Note the fact that because I multiplied the figure by a negative sign, I had to reverse the less than to greater than signage.

domain is (-∞, -√3.5]U[√3.5, +∞)

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