Michelle, we can solve this using substitution in a system of equations.
Let's let s = the smaller number and l = the larger. In this case, we have l = s + 5.
We also have 2s + 28 = -7l
Since the first equation is already solved for l, we can substitute the "value" of l into the 2nd equation.
2s + 28 = -7(s + 5)
2s + 28 = -7s -35
9s = -63
s = -7
So, l = -2
Let's check. 2(-7) + 28 =-2(-7)
-14 + 28 = 14
14 = 14
Check!
Hope this helps!