How do I write this is standard form: y= 2(t-1)^2+12

Question

How do I write this equation in standard form? ax^2+bx+C

Answer 1

y = 2(t - 1)² + 12

 

y = 2*(t - 1)*(t - 1) + 12

 

y = 2*[t² - 2t +1] + 12

 

y = 2t² -4t + 2 + 12

 

y = 2t² - 4t + 14

 

Standard form:  In this case a=2, b = -4 and c = 14

Answer 2

Hi Megan;

y= 2(t-1)²+12

 

 

Let's begin with... (t-1)²

(t-1)(t-1)

Let's FOIL...

FIRST...(t)(t)=t²

OUTER...(t)(-1)=-t

INNER...(-1)(t)=-t

LAST...(-1)(-1)=1

t²-2t+1

 

Let's multiply by 2...

2(t²-2t+1)

2t²-4t+2

 

Let's add 12...

2t²-4t+2+12

2t²-4t+14