How do I write this equation in standard form? ax^2+bx+C 11/5/2013 | Megan from Muncie, IN | 2 Answers | 0 Votes Mark favorite Subscribe Comment
y = 2(t - 1)^{2} + 12 y = 2*(t - 1)*(t - 1) + 12 y = 2*[t^{2} - 2t +1] + 12 y = 2t^{2} -4t + 2 + 12 y = 2t^{2} - 4t + 14 Standard form: In this case a=2, b = -4 and c = 14 11/5/2013 | William S. Comment
Hi Megan; y= 2(t-1)^{2}+12 Let's begin with... (t-1)^{2} (t-1)(t-1) Let's FOIL... FIRST...(t)(t)=t^{2} OUTER...(t)(-1)=-t INNER...(-1)(t)=-t LAST...(-1)(-1)=1 t^{2}-2t+1 Let's multiply by 2... 2(t^{2}-2t+1) 2t^{2}-4t+2 Let's add 12... 2t^{2}-4t+2+12 2t^{2}-4t+14 11/5/2013 | Vivian L. Comment