2x^2+4x=16

Question

Solve

 

2x^2+4x=16

Answer 1

2x² + 4x = 16            Move 16 to the left to help solve the problem

2x² + 4x - 16 = 0       Now factor out 2 from the equation

2(x² + 2x - 8) = 0      Now look at the factors of -4 that subtract to get a +2

2(x + 4)(x - 2) = 0     Now set the parts equal to 0 and solve

2 = 0

not a solution

 

x + 4 = 0

   - 4     -4

x = -4

 

x - 2 = 0

  +2    +2

x = 2

 

The solutions are (-4, 2)