Solve

2x^2+4x=16

Solve

2x^2+4x=16

Tutors, please sign in to answer this question.

Orlando, FL

2x^{2} + 4x = 16 Move 16 to the left to help solve the problem

2x^{2} + 4x - 16 = 0 Now factor out 2 from the equation

2(x^{2} + 2x - 8) = 0 Now look at the factors of -4 that subtract to get a +2

2(x + 4)(x - 2) = 0 Now set the parts equal to 0 and solve

2 = 0

not a solution

x + 4 = 0

- 4 -4

x = -4

x - 2 = 0

+2 +2

x = 2

The solutions are (-4, 2)

Steven M.

Premium Test Prep and Subject Tutor - New York City UWS

New York, NY

5.0
(178 ratings)

Nikunj P.

Math and Science Specialist, Over 14 Years of Educational Experience

Scarsdale, NY

4.9
(88 ratings)

Justin H.

Math, Computer Science, and SAT Tutoring from a Google Engineer

Harrison, NJ

5.0
(329 ratings)

- Algebra 1 3023
- Math 6728
- Algebra 3736
- Math Help 3963
- Precalculus 1184
- Geometry 1369
- Word Problem 3735
- Algebra Help 868
- Trigonometry 1123
- Algebra 2 Question 425

Find a tutor fast. Get the app.

Are you a tutor? Get the app for tutors

© 2005 - 2016 WyzAnt, Inc. - All Rights Reserved