Arthur D. answered 12/08/15
Tutor
4.9
(283)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
x=# of students
y=cost per student
xy=2010
(x-y)(y+16.75)=2010
xy-10y+16.75x-167.5=2010
xy-10y+16.75x-167.5-2010=0
xy-10y+16.75x-2177.5=0
from xy=2010 you get y=2010/x
substitute
x(2010/x)-10(2010/x)+16.75x-2177.5=0
2010-(20,100/x)+16.75x-2177.5=0
multiply both sides by x
2010x-20,100+16.75x2-2177.5x=0
combine like terms
16.75x2-167.5x-20,100=0
multiply both sides by 4 to eliminate the decimals
67x2-670x-80,400=0
divide both sides by 67
x2-10x-1200=0 (if you don't see that 40*30=1200 and 40-30=10, then factor 1200 and proceed from there)
1200=2*2*2*2*3*5*5
regroup the factors
1200=(2*2*2*5)*(2*3*5)=40*30 and 40-30=10, the coefficient of the middle term
factor
(x-40)(x+30)=0
x-40=0
x=40 original students who were going to pay $50.25 each
40-10=30 students now are participating in the project and each will pay $67
30*$67=$2010
40*$50.25=$2010