Elizabeth H. answered 12/05/15
Tutor
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MFA in Theatre Loves Math K-12, Shakespeare, and Study Prep
The question seems a bit confusing, but I think I've figured out what they're looking for. It's $0.95/lb of the candy mixture, and so how many pounds of each candy do you have in a 9 lb. mix? This is what I've done...
Alright, here's what we know:
0.89*c+1.31*m=0.95
0.89*c+1.31*m=0.95
c+m=1
1) c+m=9 I need to subtract m from both sides
1) c+m=9 I need to subtract m from both sides
c+m-m+9-m
c=1-m
2) I will substitute (9-m) in for c in the top equation so....
0.89*(1-m)+1.31*m=0.95
3) Now i'm left with an equation to work out. I'm solving for m.
0.89*(1-m)+1.31*m=0.95
0.89-0.89*m +1.31*m=0.95
I want to combine like terms, so I can add the 2 m's up.
0.89+0.42*m=0.95
I want to get the variable (m) by itself, so I know how much it is. I need to use the order of operations.
0.89+0.42*m=0.95
-0.89 -0.89
0.42*m=0.06
0.42*m/0.42=0.06/0.42
m=0.06/0.42
m=(rounded)0.14286 or...
m=(not rounded) 1/7 lb.
4) if m=1/7 lb, then we can solve the 2nd equation for c
c+m=1
c+1/7=1 (whatever we do to one side, we do to the other!)
-1/7 -1/7
c=1-1/7
c=6/7
5) So, 6/7 of the 9 lb. mixture is worth $0.89/1 lb, and 1/7 of the 9 lb. mixture is worth $1.31/1 lb.
9 lbs * 6/7 = about 7.71 lbs
9 lbs * 1/7 = about 1.29 lbs
There you go. Let me know if I this helps!