
Mark M. answered 12/02/15
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Mathematics Teacher - NCLB Highly Qualified
28 = 128(0.5)6/h divide both sides by 128
0.21875 = (0.5)6/h take natural log of both sides
ln 0.21875 = (6/h) ln 0.5 calculate
-1.5198 ≈ (t/h) (-0.6931) divide both sides by -0.6931
2.19 ≈ 6/h take reciprocal
0.456 ≅ h/6 multiply both sides by 6
2.736 ≈ h
The half-life is approximately 2.7 hours.