Youngkwon C. answered 12/01/15
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Hi Leva,
As the equipment A produces 12% of a daily output,
the probability that the equipment A generates a defective every day is
0.03 · 0.12 = 0.0036.
As the equipment B produces 88% of a daily output,
the probability that the equipment B generates a defective every day is
the probability that the equipment B generates a defective every day is
0.07 · 0.88 = 0.0616.
So, the answer is
0.0616/(0.0036+0.0616) = 0.9448