
Tim E. answered 11/29/15
Tutor
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Comm. College & High School Math, Physics - retired Aerospace Engr
OK, We are given the total weight of the 4 different fish = 1092 lbs
The weights are not given, only the ratios. Let's first define a variable for each fish by 2 letters.
TP = tarpon AM = amberjack WM = white marline TN = tuna
now the ratios:
#1 TP = 2*AM (tarpon is 2x the amberjack)
#2 WM = 2*TP (white marlin is 2x the tarpon)
#3 TN = 5*AM (tuna is 5x the amberjack)
since all but the WM is defined by a ratio of the AM we can define
WM = 2*TP = 2*(2*AM) (since TP = 2*AM) or
#4 WM = 4*AM
So, the 4 fish can be represented as ratios of AM, and their total = 1,092
1092 = TP + WM + TN + AM (substituting the ratios of each below, we get:
1092 = 2*AM + 4*AM + 5*AM + AM
1092 = 12*AM so
AM = 1092/12 = 91 (now just substitute the 91 LBS for AM in each eqns 1-4)
TP = 2*AM = 2*91 = 182
WM = 4*AM = 4*91 = 364
TN = 5*AM = 5*91 = 455
As a check, add each fish's weight.
AM + TP + WM + TN = 91+182+364+455 = 1,092 LBS
David W.
11/29/15