Mark M. answered 11/27/15
Tutor
4.9
(954)
Retired Math prof with teaching and tutoring experience in trig.
T(t) = 62.6 + (86.6 - 62.6)e-kt
= 62.6 + 24e-kt
= temperature of body t minutes after 8:31 PM
T(89) = temperature of body at 10 PM
= 62.6 + 24e-89k = 78.6
24e-89k = 16
e-89k = 0.6666666
-89k = ln(0.6666666)
k = -0.0045558
T(t) = 62.6 + 24e-0.0045558t
To find the time of death, solve the equation T(t) = 98.6:
62.6 + 24e-0.0045558t = 98.6
24e-0.0045558t = 36
e-0.0045558t = 1.5
-0.0045558t = ln1.5
t = -88.99976 minutes
The time of death was 88.99976 minutes before 8:31 PM, or at about 7:02 PM. Assuming that Josh was on time for his exam, he would have been taking the exam at 7:02 PM, so he could not have committed the crime.