Michael J. answered 11/27/15
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Effective High School STEM Tutor & CUNY Math Peer Leader
x2 + y2 = 52 eq1
x2 + 10y = 76 eq2
We can subtract eq2 from eq1 to eliminate the x2 terms. This is called the elimination method.
y2 - 10y = -24
Now we have an equation in terms of y only. Solve for y from this equation.
y2 - 10y + 24 = 0
(y - 6)(y - 4) = 0
y = 6 , y = 4
Next, we substitute these values into eq1 to solve for x.
x2 + 62 = 52 and x2 + 42 = 52
x2 + 36 = 52 and x2 + 16 = 52
x2 = 16 and x2 = 36
x = -4 x = -6
x = 4 and x = 6
So we have for pairs of solutions.
x = -4 x = -6
y = 6 y = 4
x = 4 x = 6
y = 6 y = 4
On your own, validate which solution pair(s) satisfy the equations.