M K.

asked • 10/21/13

(FIRST PART ALREADY ANSWERED AND NEW PART ADDED) Why do you find the domain of both the numerator and denominator in a rational equation? When do you do it?

For example, if you had:
 
x-3
------
5x+3
 
you'd only find the domain and use the denominator. Why wouldn't you also do the numerator? 
 
And then you'd use both the  numerator and the denominator in this:
 
(x^4-9x^2)^1/2
------------------------
x^2-4
 
WHY DO YOU USE BOTH OF THEM THERE? WHY NOT ON THE FIRST ONE?
 
~NEW QUESTION~
 
So if it was linear, like the first example, then you'd only have to use the denominator to find the domain because, mainly, your only concern is that the denominator may be 0, which then would make the value not real. But for the second example, you have to use both the numerator and the denominator because they contain a root, and roots (if they're even) could make the situation imaginary thus not real. But what if the root in the denominator was a cube root?

For example

cube root (6x+3)
-----------------------
x^2-4

Would you need to use the numerator then?
 
 

1 Expert Answer

By:

Shannon H. answered • 10/21/13

Tutor
4.9 (352)

Mathematics and Science Tutor

M K.

So if it was linear, like the first example, then you'd only have to use the denominator to find the domain because, mainly, your only concern is that the denominator may be 0, which then would make the value not real. But for the second example, you have to use both the numerator and the denominator because they contain a root, and roots (if they're even) could make the situation imaginary thus not real. But what if the root in the denominator was a cube root? 
 
For example
 
cube root (6x+3)
-----------------------
x^2-4
 
Would you need to use the numerator then? 
 
Thank you very much. You've already been a great help!
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10/21/13

Shannon H.

Yes.  So if it was linear, like the first example, then you'd only have to use
the denominator to find the domain because, mainly, your only concern
is that the denominator may be 0, which then would make the value not
real. Yes.  But for the second example, you have
to use both the numerator and the denominator because they contain a
root, and roots (if they're even) could make the situation imaginary
thus not real. But what if the root in the denominator was a cube root? Cube roots or any odd root can be any x value, so no need to use the numerator, then.  If you have any other questions, just look at a graph, you will be able to see where the graph will not be continuous just focusing on the end points.  Best of luck, Shannon
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10/21/13

M K.

Thanks so much! I totally understand, and now I think I'll do great on my quiz!
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10/21/13

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