What is the length of the transverse axis of the hyperbola defined by the equation (y+2)^2/11^2-(x-6)^2/9^2=1

Question

What is the length of the transverse axis of the hyperbola defined by the equation (y+2)^2/11^2-(x-6)^2/9^2=1

Answer 1

[ (y+2)² / 11² ] - [ (x-6)² / 9² ] = 1

First, note how the denominator of the positive term on the left is 11². On a hyperbola, this is always the a² term, or in other words, the square of the distance between the center and each vertex. The length of the transverse axis of any hyperbola is 2a. In this case, it is 2 * 11 = 22 .