^{2}+b

^{2}=c

^{2}

^{2}+2

^{2}=c

^{2}

^{2}

its math homework

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Hi Tony;

I have struggled, and cannot fully answer the question.

I will give you all the information I have.

(2,2) (6,4)

The x-coordinates, 6-2, are of the length of 4 units.

The y-coordinates, 4-2, are of the length of 2 units.

This is a triangle. We trying to analyze the hypotenuse.

a^{2}+b^{2}=c^{2}

4^{2}+2^{2}=c^{2}

16+4=20=c^{2}

c is √20. This is the length of the line within the provided coordinates.

The point which corresponds to the distance from either provided coordinate ((2,2) (6,4)), to (√20)/2, is what we are looking for. I have tried to calculate these coordinates, and thoroughly discussed this with someone else. I am stuck. If you find the solution, please tell me.

The midpoint formula is as follows:

The midpoint between two points (x1, y1) and (x2, y2) is determined by the following formula:

((x1 + x2)/2, (y1 + y2)/2)

Write the formula in traditional fractional form before doing the problem.

Hi,

You need to recall the formula to find the mid point.

The coordinates of the mid point must qualify the following formula:

((x_{1} + x_{2})/2,(y_{1} + y_{2})/2)

where P_{1}(x_{1},y_{1}) and P_{2}(x_{2},y_{2})

Now your job is to figure out the coordinates of these two points and use the formula to find the answer.

Hope it helps.

Quan.

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