what is the mid point for (2,2) (6,4)

Question

its math homework

Answer 1

Hi Tony;

I have struggled, and cannot fully answer the question.

I will give you all the information I have.

(2,2) (6,4)

The x-coordinates, 6-2, are of the length of 4 units.

The y-coordinates, 4-2, are of the length of 2 units.

This is a triangle.  We trying to analyze the hypotenuse.

a²+b²=c²

4²+2²=c²

16+4=20=c²

c is √20.  This is the length of the line within the provided coordinates.

 

The point which corresponds to the distance from either provided coordinate ((2,2) (6,4)), to (√20)/2, is what we are looking for.  I have tried to calculate these coordinates, and thoroughly discussed this with someone else.  I am stuck.  If you find the solution, please tell me.

Answer 2

Hi,

You need to recall the formula to find the mid point.

The coordinates of the mid point must qualify the following formula:

((x₁ + x₂)/2,(y₁ + y₂)/2)

where P₁(x₁,y₁) and P₂(x₂,y₂)

Now your job is to figure out the coordinates of these two points and use the formula to find the answer.

Hope it helps.

Quan.

Answer 3

 

The midpoint formula is as follows:

 

The midpoint between two points (x1, y1) and (x2, y2) is determined by the following formula:

 

((x1 + x2)/2, (y1 + y2)/2)

 

Write the formula in traditional fractional form before doing the problem.