Since this problem is given in a precalculus course, I will not use Calculus to solve it.
The volume of the cylinder = pi x r^2 x h = 200
------- h = 200/(pi x r^2)
Surface area = 2 x pi x r^2 + 2 x pi x r x h
= 2 x pi x r^2 + 400/r
Use a graphing utility to graph
y = (2 pi) x^2 + 400/x
From your graph, locate the value of x at which y is a mximum.
x = 3.2 units