Write a slope intercept equation for a line parallel to the line x-8y=3 which passes through the point (16,-5)

Just a different way of doing it...

Get this into y = mx + b format so you will know the slope, m.

x - 8y = 3

Subtract x from both sides.

-8y = -x + 3

Divide both sides by -8:

y = (1/8)x -3/8

So m = 1/8.

Since line is parallel to y=(1/8)x - 3/8, it's slope must also be 1/8.

Use point-slope formula with (16, -5).

y - y

_{1}= m (x - x_{1})y - (-5) = (1/8) (x - 16)

y + 5 = (1/8)x - 2

Subtract 5 from both sides:

y = (1/8)x - 2 - 5

y = (1/8)x - 7