Draw a right triangle with right angle at the site of the grave.
Let x = height of ghost after t seconds
= length of vertical leg at time t
80 = length of horizontal leg
y = length of hypotenuse at time t
θ = angle of elevation of ghost at time t
Given: dθ/dt = 3°/sec = (3°/sec)(π/180°) = π/60 rad/sec
Find: dx/dt when x = 6 ft
Solution: tanθ = x/80
So, sec2θ(dθ/dt) = (1/80)(dx/dt)
dx/dt = 80sec2θ (dθ/dt) When x = 6, y2 = 62 + 802
y = √6436
dx/dt = 80(√(6436))/80)2(π/60)
≈ 4.21 ft/sec