
Jordan K. answered 10/30/15
Tutor
4.9
(79)
Nationally Certified Math Teacher (grades 6 through 12)
Hi Ekene,
A nice passel of problems !!
We'll consider each one in turn, below:
Problem #1:
(pi/6)(180/pi) = 180/6 = 30 degrees
The angle (-pi/6) or (-30 degrees) lies in quadrant IV where x is positive and y is negative.
sin(-30) = y/r
-0.5 = y/2
y = 2(-0.5)
y = -1
cos(-30) = x/r
√3/2 = x/2
x = √3
(2,-pi/6) = (√3,-1)
Problem #2:
f(x) = x2 + 3x + 2 (standard form)
Convert to vertex form by completing the square:
x2 + 3x + 2 = 0 (set f(x) to 0)
x2 + 3x = -2
x2 + 3x + [1/2(3)]2 = -2 + [1/2(3)]2
x2 + 3x + (1.5)2 = -2 + (1.5)2
x2 + 3x + 2.25 = -2 + 2.25
(x + 1.5)2 = 0.25
(x + 1.5)2 - 0.25 = 0 (set f(x) to zero)
Vertex form:
f(x) = a(x - h)2 + k
vertex (h,k)
f(x) = (x + 1.5)2 - 0.25
vertex (-1.5,-0.25)
Problem #3:
Exponential Decay formula:
F = Nekt
F (final amount) = 70% of N = 0.7N
N(initial amount) = N
k(rate of decay) = -0.5 (minus sign, decrease)
t(time) = unknown
Solving for unknown (t):
0.7N = Ne-0.5t
0.7 = e-0.5t
ln(0.7) = ln(e-0.5t)
ln(0.7) = (-0.5t)ln(e)
ln(0.7) = (-0.5t)(1)
ln(0.7) = -0.5t
t = ln(0.7)/-0.5
t = -0.3567/-0.5
t = 0.7134 (fraction of half life time)
(5,730)(0.7134) = 4,087.782
4,087.782 ≈ 4,088 years old
Problem #4:
Equation #1: x + y + z = 6
Equation #2: 2x - y + z = 3
Equation #3: x + y - z = 0
Equation #4: Equation #1 - Equation #3
Equation #4: 2z = 6
2z = 6
z = 6/2
z = 3
Equation #5: Equation #2 + Equation #3
Equation #5: 3x = 3
3x = 3
x = 3/3
x = 1
Equation #1:
x + y + z = 6
1 + y + 3 = 6
y + 4 = 6
y = 6 - 4
y = 2
Solution: (1,2,3)
Check (Equation #1):
x + y + z = 6
1 + 2 + 3 = 6
3 + 3 = 6
6 = 6
Check (Equation #2):
2x - y + z = 3
2(1) - 2 + 3 = 3
2 - 2 + 3 = 3
0 + 3 = 3
3 = 3
Check (Equation #3):
x + y - z = 0
1 + 2 - 3 = 0
3 - 3 = 0
0 = 0
Problem #5:
Equation #1: 2x + 3y = 7
Equation #2: 3x - 5y = 1
Equation #3: 3 times Equation #1
Equation #3: 6x + 9y = 21
Equation #4: 2 times Equation #2
Equation #4: 6x - 10y = 2
Equation #5: Equation #3 - Equation #4
Equation #5: 19y = 19
19y = 19
y = 19/19
y = 1
Equation #1:
2x + 3y = 7
2x + 3(1) = 7
2x + 3 = 7
2x = 7 - 3
2x = 4
x = 4/2
x = 2
Solution: (2,1)
Check (Equation #1):
2x + 3y = 7
2(2) + 3(1) = 7
4 + 3 = 7
7 = 7
Check (Equation #2):
3x - 5y = 1
3(2) - 5(1) = 1
6 - 5 = 1
1 = 1
Thanks for submitting these problems & glad to help.
God bless, Jordan (Romans 5:8)