Raymond B. answered 08/05/23
Math, microeconomics or criminal justice
Descartes rule of signs
ax^3 +bx^2 +cx + d = 0
has a maximum number of positve real zeros equal to the number of sign changes
from a to be to c to d
if all are the same sign, there are no positve real zeros
if they alternate in sign, there is a maximum 3 positive real zeros
if one sign change, just one possible positive real zero
if two sign changes, then two possible positive real zeros
then to find the number of possible negative real zeros
substitute -x for x in the polynomial, then count the number of sign changes. the number of sign changes = the maximum number of negative real zeros
for example, if there is only 1 sign change for x, and no sign changes for -x, then there is 1 positive real zero and no real negative zeros. that leaves 2 imaginary zeros, they come in conjugate pairs
fundamental theorem of algebra gets more complicated and comes in several equivalent versions. See the wikipedia article.