The equation of line l is 6x-3y=4. Line m is perpendicular to line l. The slope of line m is

Question

help me  i need someones help just to hard for me

Answer 1

Hi Jerry, what you need to know is the relationship of perpendicular lines. For lines to be perpendicular, if you multiply their slopes the result will equal -1.

 

Slope of line 1 is m₁ and the slope of line 2 is m₂. If the lines are perpendicular, then m₁ * m₂ will equal -1.

 

For the given line, the slope will be A / -B, where A is the value associated with the x term and B is the value associated with the y term. In this example, A = 6 and B = -3. Then the slope of the line is 6 / -(-3) or 2.

 

The slope of the second line can be found by what we know about perpendicular lines, or m₁ * m₂ = -1.

 

We know m₁, which is 2. Substituting for m₁ in the formula gives:

 

2 * m₂ = -1

 

Divide both sides by 2 gives:

 

m₂ = -1/2

 

The slope of the second line is -1/2.

 

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