Arthur D. answered • 10/17/15
Tutor
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(283)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
d=rt
d=45*t
d=54*(t-0.2) 12 minutes=12/60=1/5=0.2 hours
equate them because the distances are equal
45t=54(t-0.2)
45t=54t-10.8
45t-54t=-10.8
-9t=-10.8
9t=10.8
t=10.8/9
t=1.2 hours
1.2-0.2=1 hour
it takes I hour for the Jac liner to overtake the Jam liner
Arthur D.
tutor
The Jac left 12 minutes or 12/60=1/5=0.2 later, so the Jac's time is 12 minutes less than the Jam's time. The Jac traveled for 12 minutes or 0.2 hours less time than the Jam.
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10/18/15
Zyan J.
10/17/15