
Andrew M. answered 10/18/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
x2-4x + 4 = 0
The discriminant is the part under the square root in the quadratic formula
x = (-b ±√(b2-4ac))/2a
The discriminant is b2-4ac
If b2-4ac > 0 then there are two real roots
If b2-4ac = 0 there is 1 real root = -b/2a
If b2-4ac < 0 there are two roots which are complex conjugates
of the format a ± bi
In this case b2-4ac = (-4)2-4(1)(4) = 16 - 16 = 0
Since the discriminant = 0 there is one real root
That root is -b/2a = -(-4)/2 = 4/2 = 2
There is only one real root so the graph only touches the x axis
at one point... (2,0). Since the coefficient of the square term is
positive this graphs as a parabola with vertex at (2,0) opening
upwards.