find the equation of the line that passes through the point (-4,15) and. is perpendicular to y=(-2/5)×-7

Question

Find the perpendicular 

Answer 1

1. The line passes (-4,15). Let m be the slope of the line. Then we can write

(y-15) = m (x+4).

Now, we need to figure out what m is.

2. the line that we want to find is perpendicular to y = (-2/5)x -7 => this implies that m * (-2/5) = -1. Therefore, m = 5/2.

 

All together, we have

y- 15 = 5/2 * (x+4)

OR

y = 5/2*x + 5/2*4 + 15 

OR

y = 5/2*x + 25

 

 

Hope this helps!