I need to find the equation of the line parallel to y=3 and it goes through points (2,-1) and put it in slope intercept form

Question

I need to find the equation of the line parallel to y=3 and it goes through points (2,-1) and put it in slope intercept form

Answer 1

Are you sure you have understood the problem correctly? The line y=3 is a horizontal line, and a horizontal line has a slope of zero. The only lines parallel to a horizontal line are other horizontal lines. Therefore, there is no slope. The slope is the coefficient of x in the slope-intercept form: y = mx + b. m stands for the slope, and b is the y-intercept.

Answer 2

Jenifer,

 

slope  = (y2 - y1) / (x2 -x1)

 

so

y - y1 = m (x -x1)

 

the point (2 , - 1)

 

Equation of a line  is  y =mx + c

 

where m is the slope

 

y =3 has zero slope so m = 0 and parrle line to this must have m = 0 as well

 

Back to the point of (2, -1)  using y -y1 = m(x -x1)

 

We will have

 

y - (-1) = m(x -2)

 

y + 1 = 0 - 0

 

y = -1

 

And you have it...

 

 

Remember that  y = 2x + 3 and y = 2x - 6 have the same slope of  m =2 (i.e. parallel)

 

Also y = 1/4x + 22/3 and y = 1/4x  + 100 also have the same  slope of  m = 1/4

 

And as well y = 8 and y = 1000 have the same slope of m = 0

 

Let me know if you have any more questions or need more help.