Arnold F. answered 10/09/15
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College Professor & Expert Tutor In Statistics and Calculus
(1) First I would find that if a single person Rh+ is selected at random then what is the probability they are O+ given they are Rh+.
P(O+|Rh+)= P(O+ and Rh+)/P(Rh+) = P(O+)/P(Rh+) since if the person is O+ they must be Rh+
= .37/.83=p
(2) Since we are sampling from a very large population we can assume a binomial distribution
P(fewer than 3)=P(0)+P(1)+P(2)=b(0,9,p)+b(1,9,p)+b(2,9,p)
b(r,n,p) represent the binomial probability of r successes in n trials with p=P(success)
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