Two numbers differ by 3. Four times the lesser decreased by three times the greater is 7. Find the numbers.

Question

Help me please thank you!

 

Answer 1

First you must write your 2 equations:

x=y-3  (x is the lesser number since it is 3 less than y)

4x-3y=7

 

Substitute:

4(y-3)-3y=7

4y-12-3y=7

y=19

 

x=19-3

x=16