an object is dropped from 49 feet below the tip of the pinnacle atop a 725-ft tall building..

Question

 The height h of the object after t seconds is given by the equation h= -16t^2+676. Find how many seconds pass before the object reaches the ground

Answer 1

0 = -16t^2 + 676

-676 =-16^t^2

-676/-16 = t^2

42.25 = t^2

√42.25 = √t^2

t = 6.5