Find the common ratio, r, for an infinite series with an initial term of 4 that converges to a sum of (16/3).

Question

 I need help fast!

Answer 1

the formula for sumof an infinite GP is 

S=a/(1-r)

 

so we have 16/3=4/(1-r)

 

1-r=12/16

r= 1-3/4

=1/4