SURENDRA K. answered 10/01/15
Tutor
New to Wyzant
An experienced,patient & hardworking tutor
4x^2-12x=2x^2-2y^2+5
(2x^2-12x)+2y^2-5=0
2(x-3)^2-5-18+2y^2=0
(x-3)^2+y^2=[sqrt(23/2)]^2
This is the equation of a circle.
Center is (3,0)
Radius = sqrt(23/2)