SURENDRA K. answered 10/01/15
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4x^2-16x+12y-8=0
4x^2-16x+16-16+12y-8=0
(2x-4)^2+12y-24=0
y=(-1/3)(x-2)^2+2
It is a parabola with vertex at (2,2)
Its axis is x=2
The parabola is inverted Downwards.