when the sum of a number plus three is squared, it is 9 more than a number plus 2 when squared

Question

help me, please! 

Answer 1

 Just choose a variable, and indicate what represent:

 

   n ---- number, then convert the the statement of program to algebraic expression and solve

 

  Just like

 

   ( n+3 ) ²     when sum of a number added 3 squared

    (n + 3 ) ²  =  ( n+2 )² + 9  more that 9 when sum plus 2 squared.

 

     Now there is a equation with one variable is set to solve.

Answer 2

Let x be that number.

 

(x+3)² is 9 more than (x+2)², that is,

 

(x+3)²=(x+2)²+9

 

x²+6x+9=x²+4x+4+9;

 

2x=4;

 

x=2;