
Steven C. answered 03/13/16
Tutor
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Mathematics Tutor Steven
We have 6 selection locations:
__ __ __ __ __ __
From these locations, two are predetermined and 10 remain in the box:
A B __ __ __ __
Thus, there are 10 chips available and we are selecting 4, so we have:
(10C4) combinations which include the two defective chips.