Deanna L. answered 09/18/15
Tutor
5.0
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Electrical engineering major and music lover with MIT degree
Heather,
Since you are given the mean and standard deviation and the data is normally distributed, this allows you to calculate a z value which corresponds to a percentage on the normal distribution range on a table. This can be found manually, through a calculator or via Excel. I'll show you how to find the z value and leave it to you to find the percentage.
First off the general formula for z=(X-m)/σ where m is the mean and σ is the standard deviation. A z lookup table will give you the percentage for all values from 0 up to X. This is important!
To find percentage of scores lower than 640, plug in X=640 to find z and then look up the percentage.
To find percentage of scores between 630 and 730, find z for X=630 and X=730 and find the difference.
To find percentage of scores between 600 and 700, find z for X=600 and X=700 and find the difference.
To find percentage of scores above 700, find z for X=700 and subtract the resulting percentage (in the form .XX) from 1. This is because all percentages total to one and we want all scores above 700, not below.
With a sample of 900 people, the z formula changes slightly because the standard deviation needs to be adjusted into something called standard error (SE). That's because standard deviation grows smaller as sample size grows bigger. Now z=(X-m)/SE where SE=σ/√n where n is the sample size. So, plug in n=900, X=750, m=700, σ=70 and find z and then the percentage. Remember we're looking for scores above 750 so you'll have to subtract the percentage from 1 to get the answer.
Hope that helps!