How many atoms are in 1.97 mol of pure aluminum?

Question

help me answer this please im about to have a mental breakdown

Answer 1

Like Roman said Avogadro's number is the key to your problem. The value that you'll use on paper is 6.022x10^23. Luckily in our case a mol specifically refers to the amount of atoms. Its a weird concept but 1.97 mol of Aluminum is the exact same amount of atoms as say helium. The only differences lay in the total mass of the sample.

 

Avogadro's number is a constant so don't plan on forgetting either.

Answer 2

Use Avogadro's number N_A.

 

(1.97 mol)N_A = (1.97 mol)(6.022140857×10²³ atoms/mol) ≈ 1.19 × 10²⁴ atoms