Arthur D. answered 09/14/15
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d=r*t
d=r*16 (freight)
d=(r+15)*12 (express)
equate the two equations because the distances are the same
16r=12(r+15)
16r=12r+180
16r-12r=180
4r=180
r=180/4
r=45 mph for the freight train
r+15=45+15=60 mph for the express train