Dealing with a weighted dice:

Question

assume that 3, 5, 6, and 2 are equally likely, a 4 is twice as likely as a 2, and a 1 is twice as likely as a 4.
(1) What is the value of w3?


(2) What is the value of w4?


(3) What is the value of w1?

Answer 1

Think of it as probability points...

 

3, 4, 6, and 2 each have 1 point

4 has 2 points

1 has 4 points

 

So there are a total of 10 points.

 

So, P(3) = 1/10

P(4) = 2/10 = 1/5

P(1) = 4/10 = 2/5