Michael J. answered 09/02/15
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Effective High School STEM Tutor & CUNY Math Peer Leader
We need the equation to have positive exponents, since quadratic equations have a degree of 2 and not -2.
Let x-1 = u
If we square both sides of the equated variable,
(x-1)2 = u2
x-2 = u2
Now we can substitute the u into the equation.
4u2 + 11u - 20 = 0
(4u + 5)(u - 4) = 0
Set the factors equal to zero.
4u + 5 = 0 and u - 4 = 0
u = -5/4 and u = 4
Now we take the solution of x. Remember that
x-1 = u
(x-1)-1 = u-1
x = 1 / u
x = 1 / (-5 / 4) and x = 1 / 4
x = -4/5 x = 1/4